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2x^2-110x-4000=0
a = 2; b = -110; c = -4000;
Δ = b2-4ac
Δ = -1102-4·2·(-4000)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44100}=210$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-210}{2*2}=\frac{-100}{4} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+210}{2*2}=\frac{320}{4} =80 $
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